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0-24=x^2-10x
We move all terms to the left:
0-24-(x^2-10x)=0
We add all the numbers together, and all the variables
-(x^2-10x)-24=0
We get rid of parentheses
-x^2+10x-24=0
We add all the numbers together, and all the variables
-1x^2+10x-24=0
a = -1; b = 10; c = -24;
Δ = b2-4ac
Δ = 102-4·(-1)·(-24)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2}{2*-1}=\frac{-12}{-2} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2}{2*-1}=\frac{-8}{-2} =+4 $
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